A advocate select 3 cases to review. The group of cases to select from include 8 robberies, 5 auto accident,?

and 2 assault cases. What it the probability of selecting 1 of each. How to sit up and solve?
Answers:
if it is EXACTLY 1 of respectively,
we must know how many of "others" are there for the 3rd
since we don't know,
"select 1 of each" here has to mean AT LEAST 1 of respectively

so reqd. probability
= [8C1*5C2 + 8C2*5C1] / 13C3
= 0.7692
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